Hypothesis

Non-isometric benefits

FlorE’s FLG ablation drops MRR 40.2 → 24.1. That does not identify Lorentz membership. D(σ) is an anisotropic scale. This page measures what that scale does to the sheet and to a two-tail ranking. It does not claim the scale caused 0.402.

One extra scalar is capacity, not a group

D(σ) scales a single Minkowski axis. That is one learned degree of freedom per FLG module. It is not an element of O(1, n) unless σ = ±1.

σ → 0 collapses an axis

Every entity’s last coordinate is zeroed. Rankings then ignore that axis. An isometry cannot do this: |det Λ| would stay 1.

The path from +1 to −1 leaves O

Continuous interpolation through σ ∈ (−1, 1) is exactly the illegal path. Householder parity jumps. Scaling walks.

FLG moved the table; isometry is not identified

40.2 → 24.1 without FLG (−16.1). 40.2 → 37.3 without DO (−2.9). The labelled FLG is Q·flip_sign, not O(1, k). The 16-point drop does not attribute to Lorentz membership.

equalizing σ ≈ 0.059 · ranking same as σ = 1

ε_group |σ²−1|

0.8400

det D

0.4000

q(Dh)+1 drift

-0.1342

q(Dh)

-1.1342

Scoreσ = 1 (isometry)this σ
d²(Dh, t₁)0.02780.3035
d²(Dh, t₂)0.85660.6038
preferred tailt1t1
margin d²₂ − d²₁0.82880.3003
failsNon-isometric. Sheet drift -0.1342. Ranking power is the illegal DoF.